Binary Search Program In C Using While Loop

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1. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions. Find the node with maximum value in a Binary Search Tree; DFS traversal of a tree using recursion. Or want to share more information about stack Morris Inorder Tree.
2. C Exercises: Convert a binary to a decimal using for loop and without using array Last update on August 29 2018 08:56:18 (UTC/GMT +8 hours) C For Loop: Exercise-42 with Solution. Write a program in C to convert a binary number into a decimal number without using array, function and while loop.

Forum Categories. Decimal to binary in while loop.stuck Home. Programming Forum Software Development Forum. (Decimal to Binary program) Difference between 'WHILE' loop and 'FOR' Loop in C language? How to convert decimal to binary.

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Given a sorted array arr[] of n elements, write a function to search a given element x in arr[].

A simple approach is to do linear search.The time complexity of above algorithm is O(n). Another approach to perform the same task is using Binary Search. Mac os x iso vmware download.

Binary Search: Search a sorted array by repeatedly dividing the search interval in half. Begin with an interval covering the whole array. If the value of the search key is less than the item in the middle of the interval, narrow the interval to the lower half. Otherwise narrow it to the upper half. Repeatedly check until the value is found or the interval is empty.

Example :
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The idea of binary search is to use the information that the array is sorted and reduce the time complexity to O(Log n).

Recommended: Please solve it on “PRACTICE ” first, before moving on to the solution.

We basically ignore half of the elements just after one comparison.

1. Compare x with the middle element.
2. If x matches with middle element, we return the mid index.
3. Else If x is greater than the mid element, then x can only lie in right half subarray after the mid element. So we recur for right half.
4. Else (x is smaller) recur for the left half.

Recursive implementation of Binary Search https://camnarethis.tistory.com/4.

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C

// C program to implement recursive Binary Search // A recursive binary search function. It returns // location of x in given array arr[l.r] is present, intbinarySearch(intarr[], intl, intr, intx) if(r >= l) { // itself returnmid; // If element is smaller than mid, then if(arr[mid] > x) // in right subarray } // We reach here when element is not return-1; { intn = sizeof(arr) / sizeof(arr[0]); intresult = binarySearch(arr, 0, n - 1, x); (result -1) ? printf('Element is not present in array') result); }

C++

// C++ program to implement recursive Binary Search usingnamespacestd; // A recursive binary search function. It returns // location of x in given array arr[l.r] is present, intbinarySearch(intarr[], intl, intr, intx) if(r >= l) { // itself returnmid; // If element is smaller than mid, then if(arr[mid] > x) // in right subarray } // We reach here when element is not return-1; { intx = 10; intresult = binarySearch(arr, 0, n - 1, x); (result -1) ? cout << 'Element is not present in array' : cout << 'Element is present at index '<< result; }

Java

// Java implementation of recursive Binary Search // Returns index of x if it is present in arr[l. intbinarySearch(intarr[], intl, intr, intx) if(r >= l) { // middle itself returnmid; // If element is smaller than mid, then if(arr[mid] > x) // in right subarray } // We reach here when element is not present return-1; publicstaticvoidmain(String args[]) BinarySearch ob = newBinarySearch(); intn = arr.length; intresult = ob.binarySearch(arr, 0, n - 1, x); System.out.println('Element not present'); System.out.println('Element found at index '+ result); }

Python

defbinarySearch (arr, l, r, x): # Check base case ifarr[mid] ==x: # can only be present in left subarray returnbinarySearch(arr, l, mid-1, x) # Else the element can only be present else: # Element is not present in the array arr =[ 2, 3, 4, 10, 40] result =binarySearch(arr, 0, len(arr)-1, x) ifresult !=-1: else:

C#

usingSystem; classGFG { // arr[l.r], else return -1 intr, intx) if(r >= l) { // middle itself returnmid; // If element is smaller than mid, then if(arr[mid] > x) // in right subarray } // We reach here when element is not present return-1; publicstaticvoidMain() intn = arr.Length; Console.WriteLine('Element not present'); Console.WriteLine('Element found at index ' }

PHP

Binary Search Using C

// PHP program to implement // function. It returns location // is present, otherwise -1 { { // at the middle itself returnfloor($mid); // If element is smaller than // present in left subarray returnbinarySearch($arr, $l, // be present in right subarray $r, $x); // is not present in array } // Driver Code $n= count($arr); $result= binarySearch($arr, 0, $n- 1, $x); echo'Element is not present in array'; echo'Element is present at index ', ?>

Output :

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C

// C program to implement iterative Binary Search // A iterative binary search function. It returns // location of x in given array arr[l.r] if present, intbinarySearch(intarr[], intl, intr, intx) while(l <= r) { if(arr[m] x) if(arr[m] < x) else } // if we reach here, then element was return-1; { intn = sizeof(arr) / sizeof(arr[0]); intresult = binarySearch(arr, 0, n - 1, x); ' in array') 'index %d', return0;

C++

// C++ program to implement recursive Binary Search usingnamespacestd; // A iterative binary search function. It returns // location of x in given array arr[l.r] if present, intbinarySearch(intarr[], intl, intr, intx) while(l <= r) { if(arr[m] x) if(arr[m] < x) else } // if we reach here, then element was return-1; { intx = 10; intresult = binarySearch(arr, 0, n - 1, x); (result -1) ? cout << 'Element is not present in array' : cout << 'Element is present at index '<< result; }

Java

// Java implementation of iterative Binary Search // Returns index of x if it is present in arr[], intbinarySearch(intarr[], intx) intl = 0, r = arr.length - 1; intm = l + (r - l) / 2; // Check if x is present at mid returnm; // If x greater, ignore left half l = m + 1; // If x is smaller, ignore right half r = m - 1; // not present } // Driver method to test above { intarr[] = { 2, 3, 4, 10, 40}; intx = 10; if(result -1) else + 'index '+ result); }

Binary Search Program In C

Python

# Search. # It returns location of x in given array arr defbinarySearch(arr, l, r, x): whilel <=r: mid =l +(r -l)/2; # Check if x is present at mid returnmid # If x is greater, ignore left half l =mid +1 # If x is smaller, ignore right half r =mid -1 # If we reach here, then the element return-1 arr =[ 2, 3, 4, 10, 40] result =binarySearch(arr, 0, len(arr)-1, x) ifresult !=-1: else:

C#

usingSystem; classGFG { // else return -1 { while(l <= r) { if(arr[m] x) if(arr[m] < x) else } // if we reach here, then element was return-1; publicstaticvoidMain() int[] arr = { 2, 3, 4, 10, 40 }; intx = 10; if(result -1) else + 'index '+ result); }

PHP

// PHP program to implement // function. It returns location // if present, otherwise -1 $r, $x) while($l<= $r) $m= $l+ ($r- $l) / 2; // Check if x is present at mid returnfloor($m); // If x greater, ignore if($arr[$m] < $x) // ignore right half $r= $m- 1; // element was not present } // Driver Code $n= count($arr); $result= binarySearch($arr, 0, if(($result -1)) else $result; // This code is contributed by anuj_67.

Output :

Time Complexity:
The time complexity of Binary Search can be written as Chief architect premier keygen.

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The above recurrence can be solved either using Recurrence T ree method or Master method. It falls in case II of Master Method and solution of the recurrence is .

Auxiliary Space: O(1) in case of iterative implementation. In case of recursive implementation, O(Logn) recursion call stack space.

Binary Search Program In C Language

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